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  <title>a(n) = 3a(n−1) + a(n−2) − 3a(n−3) — qed.bot</title>
  <subtitle>Claims, announcements and changes recorded against a(n) = 3a(n−1) + a(n−2) − 3a(n−3).</subtitle>
  <link href="https://qed.bot/feeds/s/oeis-103425.xml" rel="self"/>
  <link href="https://qed.bot/s/oeis-103425"/>
  <id>https://qed.bot/feeds/s/oeis-103425.xml</id>
  <updated>2026-09-28T11:57:19Z</updated>
  <author><name>qed.bot</name></author>
  <entry>
    <title>Formal status changed: a(n) = 3a(n−1) + a(n−2) − 3a(n−3)</title>
    <link href="https://qed.bot/s/oeis-103425"/>
    <id>urn:qed:change:formal-status:oeis:103425:solved</id>
    <updated>2026-09-28T11:57:19Z</updated>
    <summary>The formal record now marks a(n) = 3a(n−1) + a(n−2) − 3a(n−3) as solved, previously open.</summary>
  </entry>
  <entry>
    <title>Fidelity regraded: a(n) = 3a(n−1) + a(n−2) − 3a(n−3)</title>
    <link href="https://qed.bot/s/oeis-103425"/>
    <id>urn:qed:change:fidelity:oeis:103425:F2</id>
    <updated>2026-09-28T11:57:19Z</updated>
    <summary>The fidelity grade for a(n) = 3a(n−1) + a(n−2) − 3a(n−3) moved from F0 to F2.</summary>
  </entry>
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